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Apparently, face sets cannot be selected directly. So to isolate them, all other face sets must be hidden. That's easy enough to pull off if you only want to work with one face set, because you can just press SHIFT + 'h'. However, if what you actually want is to combine one face set with another face set to end up with one single face set, it's no use to isolate one face set by hiding all the others. You need two face sets to remain unhidden, so that you can then select them both in Edit Mode and choose "Face Set from Edit Mode Selection" in Sculpt Mode to turn them into one single face set. So the only way to get two or more face sets to be the only visible ones is by manually hiding all the other face sets, one by one. This can't be the expected workflow. There simply must be a way to select face sets directly, and to combine two face sets into a single selection of faces, so that you can combine them into one face set.

If there's a different workflow for achieving the consolidation of face sets, I don't know what it is.

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I have no idea how to select more than one face set, so the only way to do it - or at least how I would do it if it is just a small amount of face sets you want to combine, like two in your example - is this, let's say I want to merge the two on the right side, the khaki and petrol colored ones:

merge two face sets

  1. Hiding the first face set with H

    hide first

  2. Then hiding the second one with H

    hide the second

  3. Choose SCulpt > Invert Visible (no shortcut, but of course you could assign a custom one)

    invert visible

  4. Merging the two face sets with Mask > Face Set from Visible

    face set from visible

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    $\begingroup$ Thanks. That is probably the best workaround. What your solution helps me see, also, is that the way to proceed when the number of face sets to combine is relatively large could theoretically be the same as what you describe here, except that one would then start by hiding the face sets which are NOT to be combined instead of by hiding the ones which are. $\endgroup$
    – R-800
    Commented Sep 12 at 18:14

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