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Hi I want to create a circular shape with polyhedra triangles. So I can push or pull the connection spots up and down.

Eventually I want to have the structure of polyhedra into a "flat" circular surface to make it in to a 4mm plate with the structure on both sides of the plate.

This is how far I've got.

UPDATE: To simplify: I don't want the spherical result. I want a "plane" with the surface of the polyhedra shape.

testleft This is sort of what I want. I want a disc with the triangulated mesh in it. So I can push-pull the point inwards and outwards. The disc itself should be 5mm thick and have the same triangulated points on the bottom as on the top.

testabove

polyhedrashape

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  • $\begingroup$ I'm a bit confused, do you want to flatten all the vertices you have and then turn it into the example below? $\endgroup$
    – Nascent Space
    Commented Sep 25, 2023 at 6:40
  • $\begingroup$ @NascentSpace No, the spherical shape hase inward and outward pushed vertices. I want to have a "flat" circulare surface with the same vertices inward and outwards. $\endgroup$
    – Quinten De Wilde
    Commented Sep 25, 2023 at 9:10
  • $\begingroup$ I think you're going to have to specify this more closely. Do you want a view of the surface's vertices projected into the flat circle's geometry, or what? Can you illustrate the desired relation between 3D and 2D? $\endgroup$
    – Robin Betts ♦
    Commented Sep 25, 2023 at 9:41
  • $\begingroup$ @RobinBetts I want a disc with the triangulated mesh in it. So I can push-pull the point inwards and outwards. The disc itself should be 5mm thick and have the same triangulated points on the bottom as on the top. $\endgroup$
    – Quinten De Wilde
    Commented Oct 2, 2023 at 19:09
  • $\begingroup$ what are "polyhedra triangles"? "So I can push or pull the connection spots up and down." - you can do it with any subdivided plane. "Eventually I want to have the structure of polyhedra into a "flat" circular surface" - and yet somehow Jag's answer doesn't satisfy you? " I want a disc with the triangulated mesh in it." - OK, create a disc, and CTRL+T triangulate it. Done. "he disc itself should be 5mm thick and have the same triangulated points on the bottom as on the top." - extrude the disc down, and triangulate again to convert side quads to triangles… $\endgroup$
    – Markus von Broady
    Commented Oct 2, 2023 at 22:51

3 Answers 3

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Indeed as stated, the question would benefit from clarifications.

Anyway, here's a tentative to answer from what I understood.

First create an icosphere that looks a bit like what you're aiming for.

enter image description here

Remove the lower part then flatten the half sphere.

enter image description here

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Using the dissolve tool (CTRL+X) and the knife tool (K), create the pattern of your liking:

enter image description here enter image description here

Finally , using proportional editing with the spherical option, grab the center part and raise it as far as you need it.

enter image description here enter image description here

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  • $\begingroup$ It's not exactly what I want. This is more flattening the object, which results in a sphere like object. I want a disc with the triangulated mesh in it. So I can push-pull the point inwards and outwards. $\endgroup$
    – Quinten De Wilde
    Commented Oct 2, 2023 at 19:07
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Create a Circle mesh. Define the number of vertices you want. Go to Edit mode, select all vertices and press F to fill with a Face. Press I to Inset just a little bit and click. Press M to merge all those points, and choose Merge at Center.

enter image description here

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I got it to work with a plugin Loop Tools.

  • making a circle.
  • Adding a grid fill then adding subdivide.
  • Extrude the whole thing

Lastly, pull the points up and down on the triangles.

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