Timeline for How can I view the perspective projection of an arbitraryy shape onto the plane below?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Mar 6 at 15:01 | history | edited | Duarte Farrajota Ramos♦ | CC BY-SA 4.0 |
Improve title and discoverability
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| Apr 9, 2017 at 5:30 | history | tweeted | twitter.com/StackBlender/status/850944097024172032 | ||
| Apr 7, 2017 at 22:36 | comment | added | Rick Riggs | It might be a little more approachable starting out to learn up on the compositor, and how to use render layers. Then you could do something like parent a light to your camera's origin, set your plane to one render layer with the default passes applied, set your cubes to another with only the shadow pass applied, and then output the 1st render layer (you have to render both though, because it needs all info). Anyway it's not completely an easy approach either, but another one to consider. | |
| Apr 7, 2017 at 18:30 | answer | added | lemon | timeline score: 9 | |
| Apr 7, 2017 at 17:48 | answer | added | Duarte Farrajota Ramos♦ | timeline score: 14 | |
| Apr 7, 2017 at 17:42 | comment | added | Rick Riggs | With your mouse over the 3D window hit the <kbd>Numpad 5</kbd> key. Keep in mind that the actual projection will be in the same 3D coordinates. How you view them is the only thing that differs. | |
| Apr 7, 2017 at 17:34 | review | First posts | |||
| Apr 7, 2017 at 18:01 | |||||
| Apr 7, 2017 at 17:29 | history | asked | user1301295 | CC BY-SA 3.0 |