Timeline for Displacement based on image with colormap
Current License: CC BY-SA 4.0
10 events
when toggle format | what | by | license | comment | |
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S Aug 6 at 18:20 | vote | accept | ComicMatrix | ||
May 29 at 22:46 | answer | added | Robin Betts♦ | timeline score: 2 | |
May 29 at 19:35 | vote | accept | ComicMatrix | ||
S Aug 6 at 18:20 | |||||
May 29 at 12:03 | answer | added | Gordon Brinkmann | timeline score: 3 | |
May 29 at 11:14 | comment | added | Gordon Brinkmann | @Gorgious There is no need to differentiate between lower left and top right quadrant. As said in the question: "I'd be happy with only a proper way to translate from color to 0-1 greyscale image." When you have an image texture providing these colors and want to convert them in a heightmap, the above is simple UV mapping. You differentiate from bottom left to top right quadrant by going from bottom left of the image to the top right of the image. The problematic thing about this is, the colors are not easily converted in a heightmap. | |
May 29 at 10:50 | comment | added | Gorgious | @GordonBrinkmann sure but how do you differentiate between a color that would put you in the lower left quadrant of the first picture and a color that would put you in the top right quadrant ? They look like they are the same color. Maybe I didn't understand the image. | |
May 29 at 7:49 | comment | added | Gordon Brinkmann | @Gorgious How color gives negative values? By mapping a positive range to a negative. If you look at a map with mountains and valleys with color-coded height information, you can surely give valleys which lie below sea level (i.e. have height value below 0) a color like blue for example? If the second colormap would not go from blue over green to yellow but from black to white, the mapping would be trivial with a Map Range node: From Min = 0, From Max = 1, To Min = -4, To Max = 6 or the other way round if you wanted to converted height above/below sea level to a greyscale range. | |
May 29 at 7:25 | comment | added | Gorgious | Hello, I don't understand how the color gives the information about negative values. If you're only going to use the V component of the HSV you'll only be able to use the top-right quadrant of your first image. I think we're missing something as it looks like the first picture is horizontally and vertically symetrical whereas the abscissa and ordinate tell a different story. Cheers | |
S May 28 at 23:34 | review | First questions | |||
May 29 at 0:20 | |||||
S May 28 at 23:34 | history | asked | ComicMatrix | CC BY-SA 4.0 |