I assume that this operation is not clear to me. When I add a new modifier, I would like a modifier (which I have already identified) to be moved to the bottom of the list of existing modifiers. I am trying to move it, but I see that it does not work if the object in question, where the "Smooth" modifier is present, is not moved. On the contrary, if the object in question is active, it is moved perfectly to the bottom.

I am using:

#ob = my object, not necessarily it must be selected, it is found by a function
#smooth = #my modifier (found through a function)
for m in ob.modifiers:
    bpy.ops.object.modifier_move_down(modifier = smooth.name)

This only works if the active object is ob.

  Do I have to overwrite the context?

I saw a similar answer to this question, but I'm not sure it's my case, I would like to understand better. Although it appears that I am not getting any errors in my case.

Note:

It seems that I have solved my problem with this solution:

for m in ob.modifiers:
    c = {}
    c["object"] = c["active_object"] = ob
    bpy.ops.object.modifier_move_down(c ,modifier = smooth.name)

I understand that the "for" loop method is not the best, as it may already be almost at the bottom, so it would "Move down" many more times than you need

I would like to move a modifier (which I have already identified) to the bottom of the list of existing modifiers. Unfortunately it does not work and I don't get why...? However, if the object is active, it moves perfectly to the bottom:

#ob = my object, not necessarily it must be selected, it is found by a function
#smooth = #my modifier (found through a function)
for m in ob.modifiers:
    bpy.ops.object.modifier_move_down(modifier = smooth.name)

This only works if the active object is ob. Do I have to override the context? There is a similar question to this but I have no idea how to apply this in my case.

It seems that I have solved my problem by overriding the context members:

for m in ob.modifiers:
    c = {}
    c["object"] = c["active_object"] = ob
    bpy.ops.object.modifier_move_down(c ,modifier = smooth.name)

Any thoughts? Is there a better way of doing that?

I assume that this operation is not clear to me. When I add a new modifier, I would like a modifier (which I have already identified) to be moved to the bottom of the list of existing modifiers. I am trying to move it, but I see that it does not work if the object in question, where the "Smooth" modifier is present, is not moved. On the contrary, if the object in question is active, it is moved perfectly to the bottom.

I am using:

#ob = my object, not necessarily it must be selected, it is found by a function
#smooth = #my modifier (found through a function)
for m in ob.modifiers:
    bpy.ops.object.modifier_move_down(modifier = smooth.name)

This only works if the active object is ob.

Do I have to overwrite the context?

I saw a similar answer to this question, but I'm not sure it's my case, I would like to understand better. Although it appears that I am not getting any errors in my case.

I assume that this operation is not clear to me. When I add a new modifier, I would like a modifier (which I have already identified) to be moved to the bottom of the list of existing modifiers. I am trying to move it, but I see that it does not work if the object in question, where the "Smooth" modifier is present, is not moved. On the contrary, if the object in question is active, it is moved perfectly to the bottom.

I am using:

#ob = my object, not necessarily it must be selected, it is found by a function
#smooth = #my modifier (found through a function)
for m in ob.modifiers:
    bpy.ops.object.modifier_move_down(modifier = smooth.name)

This only works if the active object is ob.

Do I have to overwrite the context?

I saw a similar answer to this question, but I'm not sure it's my case, I would like to understand better. Although it appears that I am not getting any errors in my case.

Note:

It seems that I have solved my problem with this solution:

for m in ob.modifiers:
    c = {}
    c["object"] = c["active_object"] = ob
    bpy.ops.object.modifier_move_down(c ,modifier = smooth.name)

I understand that the "for" loop method is not the best, as it may already be almost at the bottom, so it would "Move down" many more times than you need