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What would be the proper scaling of gravity when scaling up a simulation?

There are two solutions, one with a caveat: You can scale the simulation speed 4X (under rigid body world - settings - speed). This will, however, increase times taken to bake the simulation (possibly ...
Planet Xtreme's user avatar
3 votes
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Mesh created with Geometry Nodes is slightly shifted compared to mesh created with XYZ Math Surface

There is an error in transposing the equation from XYZ Math Surface code to LaTeX. The last part of $z(u,v)$, computed in the frame "Z Equation Term 2", is written as: $$ z(u,v) = (...) - \...
StefLAncien's user avatar
  • 4,847
1 vote

What would be the proper scaling of gravity when scaling up a simulation?

When you scale your simulation you do not scale the gravity vector. Instead you multiply the simulation speed by the square root of the scale. You can set it in the Rigid Body World settings. For 16x ...
Mkarkus's user avatar
  • 36
1 vote

How do I render the implicit function z^2 + (x-y-1)(z) + y = 0 in Blender?

(Using Blender 3.6.8) Analysis Let $f(x,y,z)$ be the function of $\mathbb{R}^3$ defined by: $$ f(x,y,z) = z^2 + (x-y-1)z + y $$ $f(x,y,z)=0$ can be interpreted as the following quadratic equation in $(...
StefLAncien's user avatar
  • 4,847
1 vote

Apply Local Rotation after Transform

Ok I found it out myself! To get the local rotation you need to inverse the rotation matrix and apply it to the cameras location: ...
Oliver Tworkowski's user avatar
1 vote

Geometry Nodes Equation/Method for bouncing objects?

This is an older question, but if anyone comes across it, I made a setup that solves the question more exactly. My solution is a series of gradually shrinking parabolas, so I would call it physically ...
david_for_you's user avatar
5 votes
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GN: How to smooth out jagged edges after deleting geometry?

(Using Blender 3.6.8) Analysis The function $f(x,y)$ is defined in the set of real numbers if and only if $(y-x+1)^2-4y \ge 0$. By restricting $(x,y) \in [0,1]^2$, this condition is equivalent to $1-\...
StefLAncien's user avatar
  • 4,847

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