I'd like to extract the user view orientation of the current 3DView. Since I didn't find a direct command to get it, my approach would be to take its matrix using bpy.context.region_data.view_matrix.transposed() and somehow convert it to a Euler rotation (ignoring its location), but I don't know how to do it.

Note that I'm not talking about a camera object but the user view.

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    $\begingroup$ Converting a matrix to euler is as simple as mat.to_euler(). Assuming your matrix is in the space you want, that should do the trick. $\endgroup$ – HENDRIX Jan 6 '18 at 15:04
  • $\begingroup$ Wow that was so much simpler than I expected. Tank you $\endgroup$ – ChameleonScales Jan 6 '18 at 16:16


Tanks HENDRIX, that was pretty simple

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    $\begingroup$ Just pasting a line, is not really helpful. $\endgroup$ – brockmann Jan 6 '18 at 17:15
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    $\begingroup$ @brockmann If more information is needed, then tell them what kind of additional information you expect. $\endgroup$ – Ray Mairlot Jan 6 '18 at 17:25

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