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today I was working on the look of a bowl in my project. It is UV unwrapped and I created a material for it.

Now I want to top border to be in a different color. When I now mix the 2 colors together that I want my mesh to have and put it into my diffuse color it will turn out white in the render. Which is confusing me since I do not even use white for the bowl.

enter image description hereenter image description here

and when I just put the Diffuse to black everything is fine.

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    $\begingroup$ Do not mix shaders (in this case Diffuse) with MixRGB node, use Mix shader instead. See blender.stackexchange.com/questions/33915/…. Mix colors either with 2 Diffuse shaders and one Mix shader or with 2 MixRGB nodes + 1 MixRGB node for mixing and 1 Dffiuse shader $\endgroup$ – Mr Zak Aug 30 '17 at 13:35
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    $\begingroup$ To clarify/expand on what Mr Zak said: that PBR dielectric group node is expecting RGB data in its Diffuse Color input socket. You've sent it BSDF shader data instead. And if it were me I would download the release candidate for 2.79 and use the Principled BSDF for PBR - much easier. $\endgroup$ – Mentalist Aug 30 '17 at 13:56
  • $\begingroup$ Oh yeah. I didnt notice that I used a Mix rgb. $\endgroup$ – Chimitsu Nagase Aug 30 '17 at 14:38
  • $\begingroup$ But I am somewhat confused now. The Mix shader also just has a green output. When I put that into the diffuse channel it renders it black but still without the red part. But I now know how I can change that. Instead of using 2 Diffuse Shader I just have to use 2 RGB inputs with the Mix rgb node. Thank you guys. $\endgroup$ – Chimitsu Nagase Aug 30 '17 at 14:44
  • $\begingroup$ read: blender.stackexchange.com/questions/33915/… $\endgroup$ – cegaton Aug 30 '17 at 15:11

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