I would like to use the z-math-surface add-on to animate a function with a free parameter like sin(x+a) where the effect of different values of "a" should become clear to the viewer.

I am quite new to blender and have read that it is not possible to change the function once the mesh is created. So I was thinking that maybe I could create a seperate function/mesh for every value of "a", copy all the vertices into the first object and create shape keys for the different values.

Is that possible?

  • $\begingroup$ Could you illustrate what the function looks like and how the animation would be? Maybe if it is simple enough it could be done with shapekeys, or deformations or other animation techniques. Please edit your question and provide some reference images of what you want to achieve. $\endgroup$ – Duarte Farrajota Ramos Feb 20 '17 at 13:04

Animate using shape keys and drivers.

Example script using z function surface addon. Default equation 1 - (a * x**2 + y**2) for a = [0..9]. Create a shape for each using bpy.ops.mesh.primitive_z_function_surface(...) (the operator from the addon) passing the substituted a to the operator as the equation property. (eg for a=3 equation="1 - (3 * x**2 + y**2)" .)

The separate objects are joined using bpy.ops.object.join_shapes()

import bpy
context = bpy.context 
# 10 shapes over 101 frames

scene = context.scene
vl = context.view_layer
shapes = 10
obs = []

for i in range(shapes):
                    equation="1 - (%d * x**2 + y**2)" % i,

    ob = context.object
    ob.name = "a=%d" % i


shape = obs.pop(0)
vl.objects.active = shape

for ob in obs:

for ob in obs:

# add a discrete driver animation (10 frames of each)
keys = shape.data.shape_keys.key_blocks

for i in range(1, shapes):
    shape = keys.get("a=%d" % i)
    d = shape.driver_add("value")
    d.driver.expression = "frame // 10 == %d" % i

Note the animation uses drivers. Make sure autorun is enabled

Make sure the Add Mesh : Extra Objects addon is enabled too

enter image description here

| improve this answer | |
  • $\begingroup$ Thanks a lot! That did the job. Took me some time to figure out that I had to activate auto-execution of python scripts, but then it worked! $\endgroup$ – Philipp Rosenberger Feb 20 '17 at 20:07

If you don't want to code the animation, you can use Animation Nodes to do that.

Animation Nodes is an addon which can be found here: https://github.com/JacquesLucke/animation_nodes/releases

Here is a setting that allows to influence a Z curve depending on the position of an empty object (but that can be almost anything including the current frame).

enter image description here

The principle is in two parts: a main loop and its execution for each iteration of the loop.

The main loop:

enter image description here

It starts from 2 parameters, a subdivided plane (1) and an empty (2).

From the plane, the vertices are extracted so that they are given as input for the execution function (7), and the other element (edges, polygons) are reported to be combine to a new mesh (4) and to create a new 'target' object (5).

From the empty, we take its location (6) which goes as input for the execution function (7).

Note that the plane can be either an existing object in the scene or generated by AN using a grid.

The execution function

enter image description here

We can see the defined inputs in (1).

The first input 'object vertices' is given by the calling node and corresponds to each vertex of the plane (the loop iterates giving 1 vertex per iteration, in this case).

The second input 'center' corresponds to the vector which is the location of the empty.

These two vectors are decomposed in (2) and (3) to get the coordinates we want.

In (4) additional parameters (they should be set outside of the loop, if needed).

In (5) an 'expression node' which takes all input parameters and allows to write the curve formula.

In (6) we recompose the vector, keeping X and Y from the input and Z from the formula.

(6) is given as output in (7) so that we can have it at the "upper level" (the loop 'caller').

| improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.