# How to order a list of vertices based upon position?

I have a list of vertices: But the list looks like this: [0, 1, 2, 3, 4, 5, 6, 7].

I need a script to sort the list to be like the order in the loop itself: [3, 2, 1, 0, 4, 5, 7, 6].

What list are you referring to?

the numbers shown in the image are indexes of each vertex in the obj.data.vertices list; a list of these indexes: [0,1,2,3,4,5,6,7] (8 vertices).

In the edges in obj.data.edges list you'll find the indexes of vertices that define the edge; sample: [[0,1],[1,2],[2,3],[0,4],[4,5],[5,7],[6,7]] (8 edges).

It feels like you want to reorder edges so you can loop them based on their index in obj.data.edges; sample: [[3,2],[2,1],[1,0],[0,4],[4,5],[5,7],[7,6]].

In that case you'll need to search for a start vertex the loop. A vertex which belongs to only one edge is a fitting approach. There are 2 of those in your sample, in this code the first appearing in obj.data.vertices list is selected:

vecount = []
for e in obj.data.edges:
while(len(vecount)-1 < max(e.vertices, e.vertices)):
vecount.append(0)
vecount[e.vertices] += 1
vecount[e.vertices] += 1
startidx = vecount.index(1)


Now obj.data.vertices[startidx] is the starting point of the loop Now you can create an array of edges, sorted from starting point towards end point:

edges = []
doneidxs = [startidx]
curridx = startidx
while (len(doneidxs ) != len(obj.data.vertices)):
for e in obj.data.edges:
if e.vertices==curridx or e.vertices==curridx:
if not e.vertices in doneidxs:
toidx= e.vertices
break;
else:
if not e.vertices in doneidxs:
toidx= e.vertices
break;
edges.append([curridx, toidx])
doneidxs.append(toidx)
curridx = toidx


Now you can apply the new order of edges by updating vertex indexes in the edge vertices arrays:

for e in obj.data.edges:
e.vertices = edges[e.index]
e.vertices = edges[e.index]
obj.data.update()


Run this code having the mesh selected (3D View, OBJECT mode), starting with pointing out that's the object you want the code to work on:

obj = context.active_object
...(above code)...