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I want to move a vertex from a 3D Cursor in a direction (vertex - center) ie from the cetner outwards.

I know I can achieve that with scaling the vertex position against the 3D cursor, but when moving the vertex by 1 unit I have to deduce the unit from distance.

enter image description here

When the vertex is 3 units from the 3D cursor and I want to move it by 1 unit. I have to scale the vertex by 1.3333...

Is there a better way to do this ?

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  • $\begingroup$ Select vertex, press G twice and input the desired value. $\endgroup$ – Paul Gonet Dec 15 '16 at 19:15
  • $\begingroup$ If I understand the feature correctly. Pressing G twice will in case of circle just move the vertices clock-wise or counter-clock-wise. I need to move the vertice from the center outwards. $\endgroup$ – Melon Therapy Dec 15 '16 at 19:26
  • $\begingroup$ Blender being a mesh based 3D modeller is very lacking in this sort of precision modeling area. I'll try and think of something, but I don't think there is any easy way to do this currently. $\endgroup$ – Duarte Farrajota Ramos Dec 15 '16 at 19:30
  • $\begingroup$ If you only want to move the vertex inwards, you can use the Inset operator, if you don't mind the extra step of creating a temporary face with F then erasing all the surplus created geometry. $\endgroup$ – Duarte Farrajota Ramos Dec 15 '16 at 19:33
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Try to use the Alt+S command, then type the desired value. enter image description here

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    $\begingroup$ Didn't know about this, very useful. This is why a love BSE :) $\endgroup$ – Duarte Farrajota Ramos Dec 15 '16 at 19:48
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    $\begingroup$ @Duarte Farrajota Ramos your comment with the Inset concept inspired me to find this solution :). I didn't understand what the OP really wanted before you posted it. $\endgroup$ – Paul Gonet Dec 15 '16 at 20:03
  • $\begingroup$ This is perfect. Is is possible to lock the movement to an axis, similar to normal transform ? $\endgroup$ – Melon Therapy Dec 16 '16 at 14:24
  • $\begingroup$ @Melon Therapy I'm affraid it's not possible. Remember that my answer isn't a proper solution but some kind of workaround. $\endgroup$ – Paul Gonet Dec 16 '16 at 18:41

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