5
$\begingroup$

How can one set up a non-emitting environment map in cycles? If I set strength to 0, it is black. I tried doing something with Light Path node, but didn't succeed so far.

Improve this question
$\endgroup$
2

2 Answers 2

Reset to default
8
$\begingroup$

Use a light path node, so that only the camera sees the environment texture but is not affecting the objects in the scene:

enter image description here

Improve this answer
$\endgroup$
6
  • 1
    $\begingroup$ just for information, is there a difference between this node setup and the diffuse ray visibility ? $\endgroup$
    – lemon
    Aug 9, 2016 at 17:15
  • 1
    $\begingroup$ @lemon Diffuse would only affect... diffuse. A glossy object would still reflect the environment $\endgroup$
    – user1853
    Aug 9, 2016 at 17:17
  • 1
    $\begingroup$ ok... I meant in the principle if you keep only camera ray in the cycles world panel ? $\endgroup$
    – lemon
    Aug 9, 2016 at 17:19
  • $\begingroup$ @lemon sorry I misread, but the answer is the same. If you disable diffuse only, it will still affect other rays: i.stack.imgur.com/m7CKi.jpg $\endgroup$
    – user1853
    Aug 9, 2016 at 17:26
  • 2
    $\begingroup$ The result will be the same, but the way Cycles arrives at is slightly different. Using the ray visibility switches prevents secondary rays from being sent to the world background. This node setup will still spawn the ray, then cause it to return 0. So the ray visibility switches are more efficient, although in this case the difference is minimal. $\endgroup$
    – JtheNinja
    Aug 9, 2016 at 18:28
0
$\begingroup$

The above answer is way more complicated than it needs to be, just use compositing.

Just in render settings set Film to transparent and Color Management > View Transform to standard

Then in the compositing tab, use nodes and put an "Alpha Over" node between the two default nodes.

This video explains it perfectly: https://youtu.be/aegiN7XeLow?t=50

Improve this answer
$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .