is there a way to detect what view global or local is active via python?
Can I set them directly somehow or at least always come back to global one? In a way where if script is executed view is moved to global no matter what view user is in.
4 Answers
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Here is a trick:
import bpy
is_local_view = sum(bpy.context.space_data.layers[:]) == 0
In "local_view" mode all layers disabled, while in "regular" mode one of them always enabled.
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1
It can be done this way:
for area in bpy.context.screen.areas:
if area.type == 'VIEW_3D':
space = area.spaces[0]
if space.local_view: #check if using local view
for region in area.regions:
if region.type == 'WINDOW':
override = {'area': area, 'region': region} #override context
bpy.ops.view3d.localview(override) #switch to global view
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$\begingroup$ Yes. It works. When I use
bpy.ops.render.render(write_still=True, use_viewport=True), I still got images containing all objects. $\endgroup$ Sep 24, 2019 at 8:32
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This check is using the context, assuming you are in the 3D view already, you can then exit with localview op;
if context.space_data.local_view:
bpy.ops.view3d.localview()
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$\begingroup$ AttributeError: 'SpaceConsole' object has no attribute 'local_view' in 2.79 $\endgroup$ Sep 24, 2019 at 8:28
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Thanks to Юрий Сивальнев, I searched the API a little more. the Object type has a property "layers_local_view." It is an eight memeber list, all false if the object is not in local view. If you know a particular object you would like to check in the local view space, then you can use this property.
def is_local(ob):
if ob.layers_local_view[0]:
return True
else:
return False
