1
$\begingroup$

enter image description here

I have tried a myriad of ways to get a child (ArmC) to have two parents (RivetD and RivetC) but I can't get it to work.

Now I realize that there are ways to "fake" constraints so that they look like they work, but for this question, I am trying to figure out if the Blender constraint system can drive objects with multiple joints like they really would function in the real world.

When rotating ArmA which drives ArmB, is it possible to have ArmC stay secured and rotate at RivetD while at the same time staying secured at RivetC which would then cause ArmB to rotate differently?

Here is the blend file: https://dl.dropboxusercontent.com/u/6647893/Forum_Help/TwoParentConstraints.zip

This is an example of what I am trying to accomplish: https://dl.dropboxusercontent.com/u/6647893/Forum_Help/Angles.jpg

| improve this question | |
$\endgroup$
  • $\begingroup$ So is your goal to allow elastic stretch to Arm C? Sliding Slot? Most often you see parallelogram configurations for Real World Objects with 4 rivets ... I have not taken the time to see if this is a absolute requirement. Can the distance between Rivet C and Rivet D be close to zero? $\endgroup$ – atomicbezierslinger Mar 8 '16 at 21:46
  • $\begingroup$ I apologize if my image was misleading. I don't want ArmC to bend or stretch at all. I would like it to produce this affect as it would be in the real world. dl.dropboxusercontent.com/u/6647893/Forum_Help/Angles.jpg $\endgroup$ – Bryson Jack Mar 9 '16 at 0:53
0
$\begingroup$

This is a typical Inverse Kinematics job, is this what you are trying to accomplish? gif

| improve this answer | |
$\endgroup$
  • $\begingroup$ Yes, that is exactly what I am trying to accomplish and I would like to know specifically if there is a way to do it using only constraints in Blender. $\endgroup$ – Bryson Jack Mar 9 '16 at 0:56
  • 1
    $\begingroup$ No, there is no way I'm aware of. Bone constraints are the way to go imho $\endgroup$ – diramazioni Mar 9 '16 at 1:14

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.