0
$\begingroup$

To start, I have an example scene setup illustrating my setup.

I have a round-ended cylinder that I've applied a Simple Deformation to taper it, and then a Curve to make it into a hooked claw or talon shape.

This claw is going to be used 20 times, adding claws to a figure (not included in scene). The claws are to share the same UV map and vertex order, and will share a bunch of other fiddly little shape adjustments. But, if I make a Linked or Object duplicate of the claw and try to translate and rotate the duplicate to where I want one of the finger or toe claws to be, it instead slides along the curve modifier.

I want to have 20 claw objects of various different origin points and XYZ rotations (and scalings!) to all have their curvature driven by one curve object, so that when I adjust curvature, they all stay in sync.

If I bake the curve in by Applying it, I can't adjust the curve any more. I can't bake the curve as a Shapekey, it's not on the top of the stack of modifiers and the Simple Deform: Taper will probably want to be adjusted for different variations of the claw. Anyways, curves/rotations are terrible as shape-keys.

Should I be using another approach? Is there a way to make the duplicates make a real linked duplicate the parent mesh, where the only things I can adjust are the Transforms from the object view?

$\endgroup$
2
$\begingroup$

If you select both the claw and the deforming curve and press Alt+D to do a linked duplicate of both of them, wouldn't that fix it?

You can then move the claw to a new position by selecting the duplicate claw and the duplicate curve, doing any transformation you want to both of them.

Because you did a 'linked duplicate' you can then still edit any of the curve objects and they will all update.

Here I have duplicated the curve and claw several times (using 'linked duplicate'), scaled them, moved them and by going into edit mode of a single curve I can edit them all at once:

enter image description here

$\endgroup$
  • $\begingroup$ In retrospect, that seems obvious. All the best solutions are :) $\endgroup$ – Emily Oct 7 '15 at 17:38

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.