I want those cylinder segments to be perpendicular along the curve. This geometry node is making the segments a bit tilted towards joints.

Geometry Node Problem

  • $\begingroup$ blender.stackexchange.com/questions/245282/… The answer to this question should be what you are looking for $\endgroup$
    – Eneary
    Aug 4 at 17:04
  • 1
    $\begingroup$ @Eneary Good idea, but this does something completely different. Here we are looking for a solution that does not take over the rotation of individual curve points, but aligns the rotation along the straight line. Resampling creates new points, and thus a rotation which deviates from the mesh created in parallel. $\endgroup$
    – quellenform
    Aug 4 at 18:15

2 Answers 2


Since the node Resample Curve creates new points along the curve with new tangents and normals, you always get interpolated values.

These are of course useless for your project, but there is a solution:

Just append the node Resample Curve before and increase the subdivision of the curve. Alternatively you can use Subdivide Curve.

This will give you enough intermediate points, avoiding interpolation at the crucial points:

enter image description here

Additionally you can use the node Curve to Points for your project. This will directly give you the correct rotation for your instances.


Maybe this is a bit over-elaborate.. but if you want to position your instances by resampling the curve, this is a possible strategy to suppress interpolation.

  • On another branch, convert the curve to a mesh with a simple line, (an extrusion) recording the end which lies on the curve.
  • Split the mesh edges
  • Delete the edge not on the curve

Now you have set of split mesh lines, exactly coincident with the evaluated curve-segments

  • From which you can transfer the edge-direction, by proximity.

enter image description here

Which makes this difference:

enter image description here

You could improve this by grouping to a suitable interface.. maybe Curve > 'Segment Tangent'?


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.