1
$\begingroup$

I have the same problem as already described and solved here:

In Compositor, is it possible to change multiple node values simultaneously even though there is no input socket?

Unfortunately, the driver does not update for me. I have tried many times, but it does not work.

What I want is to control from the Blur Node the Blur Size with the Node Group Input.

The blur node with drivers:

enter image description here

The Node Group value:

enter image description here

The Driver:

enter image description here

Is there a workaround for this? Or can I get the driver to update each?

$\endgroup$
4
  • $\begingroup$ pls show us at least your node tree $\endgroup$
    – Chris
    Mar 24, 2022 at 7:19
  • $\begingroup$ it works for me, but i don't know what you did - so to be sure what your problem is the best would be if you provide your blend file $\endgroup$
    – Chris
    Mar 24, 2022 at 7:21
  • $\begingroup$ Updated the question. I'm afraid I don't see where I can add a .blend file, but with the images it should be much easier to understand. The driver then works when you add it, but when I make changes in the node input afterwards, nothing happens. $\endgroup$
    – Andi
    Mar 24, 2022 at 8:30
  • $\begingroup$ thanks for clarifying and your screenshots. I wrote an answer. I hope you wanted that. $\endgroup$
    – Chris
    Mar 24, 2022 at 9:01

1 Answer 1

2
$\begingroup$

hover over your input socket value, copy as new driver, go into the node group, paste it in your value (e.g. x)

result:

enter image description here

$\endgroup$
3
  • 2
    $\begingroup$ Oh my god...that's exactly what I did. But when I tried it now, it worked! The reason: Apparently the driver is not updated when the NoteGroup is not connected. This is possibly a bug, I could imagine.... Thanks a lot for your help! $\endgroup$
    – Andi
    Mar 24, 2022 at 9:41
  • 1
    $\begingroup$ you are welcome $\endgroup$
    – Chris
    Mar 24, 2022 at 9:49
  • 2
    $\begingroup$ I don't think it's a bug. It's rather an optimization. If a node is not connected to anything, it is not computer to save on computing time. It just doesn't take into account the fact that the node inputs are animated $\endgroup$
    – Gorgious
    Mar 24, 2022 at 11:24

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .