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I'm looking for an efficient way to get the current .blend file name, in a python script.
I know how to get its path, with bpy.path.abspath('//'), but it returns only the current path, without the file name. I'm sure it's possible, but I can't find out how.
It's in bpy.data.filepath.
This is the absolute path to the currently open blend file, see is_saved, and is_dirty too.
You can get the filename with bpy.path.basename(bpy.context.blend_data.filepath). This will return it as a string without the path attached. Use for Windows compatibility and some more info here.
If you run Python script directly from a Unix Shell with a Blender as interpreter you may use one of below:
#!blender -P
import os,sys
print("OS.PATH.ABSPATH(__FILE__): "+ os.path.abspath(__file__))
print("SYS.ARGV[-1]: " + sys.argv[-1])
os.path.abspath(__file__) will give you an absolute path (relpath() available as well).
sys.argv[-1] will give you a relative path.
