# How to wrap the rope around the drum

You have to wind the wire rope on the left at number 1 and then wind it again at number 2, is there a way to draw a curve and follow it?

• have you tried with a Curve modifier for your rope? (also please avoid "help me" and "I'm going crazy") Commented Feb 3, 2022 at 9:17
• sorry, i'm don't speak english, so i missed here's rule. i never do that words Commented Feb 3, 2022 at 9:21
• There is a tutorial for rigging a drawbridge here. Unfortunately the instructor is explaining the technique in English with a heavy French accent which you might find difficult to understand. Commented Feb 3, 2022 at 9:30
• Another tutorial here. Commented Feb 3, 2022 at 9:57
• The drawbridge toot fails to fix the chain to the spool (the coil slides along it) Check out one of the answers here Commented Feb 3, 2022 at 12:43

R X 90

Shift A -> Curve -> Curve Spirals -> Archimedian

change settings like this:

Tab -> edit mode

select this vertex

E Z 8

Tab

Shift A -> Mesh -> Cylinder

Tab -> CTRL R

Tab

select Curve

CTRL A -> Location

enter 50 in z location, keyframe location on frame 1

enter 30 in z location , keyframe location at frame 50

result:

• Here I go, supplementing one of your answers again. I hope you don't mind. I'd written mine, when yours turned up and did the job. :) Commented Feb 4, 2022 at 9:02
• thank you!! of course i don't mind Commented Feb 4, 2022 at 9:10

• The distance the rope has to be translated per revolution of the large spool with a spiral diameter of D is strictly sqrt((D*pi)^2 + h^2), where h is the height per wind of the spiral. But if h is small, D*pi will probably do.
• The rate at which the small spool with diameter d must rotate is D/d times the rate at which the large spool rotates.
• The pattern on the rope must match at the beginning and end of the temporal loop. In the example below, the loop is at a 180⁰ turn of the large spool. Perhaps the easiest way to achieve the match is to make the cable an array of elements, each one of which has a length of D*pi (or, strictly, again, the expression above) and ensure a match between the ends of the elements, successfully merged by the Array modifier.
• So there is no jump in the animation of the small spool, its visible features must loop at the same time as those of the large spool. Most simply, d can divide D by a whole number.