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All tutorials I find are for 20 sided balls, based on an Ico spehere. Is there an easy solution to get a 12 sided ball? Thank you!

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    $\begingroup$ A dodecahedron has 12 sides. Is a subdivision surface (simple) and cast modifier acceptable? $\endgroup$
    – Timaroberts
    May 5, 2021 at 11:09
  • $\begingroup$ That was the term I was looking for! Thanks! $\endgroup$
    – Jurian
    May 5, 2021 at 13:25

1 Answer 1

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choose this here:

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then this:

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and you get:

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you need this add-on enabled for this functionality:

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