I have a script that goes through all of the actions in bpy.data.actions. for action in bpy.data.actions: First, is there a way to return the object the action is associated with and second, is there a way to return whether or not that object is selected? Any help is greatly appreciated!


Make a lookup table.

In going the other way can look at all objects in blend and from their animation data check all actions either assigned directly or via the NLA.

For example sake have used a defaultdict assigned to a set. Iterated over all objects and added all assoc. actions to set.

import bpy
from collections import defaultdict

actions = defaultdict(set)
for ob in bpy.data.objects:
    if not ob.animation_data:
    ad = ob.animation_data
    if ad.action:
    actions[ob.name].update(s.action for t in ad.nla_tracks for s in t.strips if s.action)
# print results

for k, v in actions.items():
    print(k, v)

Example output

Cube {bpy.data.actions['Action'], bpy.data.actions['CubeAction.002'], bpy.data.actions['CubeAction']}

Once we have created lookup above can iterate over actions where any that intersect actions[ob.name] are associated with object ob

An object is selected if ob.select_set() is True

Alter above and use for ob in context.selected_objects: to only look at actions assigned to selected objects in the context scene. (context = bpy.context If we make test code using context it pastes nicely into operator / panel code)

When an action is created by keyframing in the UI the action is assigned name, for example on object "Cube", "CubeAction" and the action is given an Action.id_root = 'OBJECT' to associate this action with objects (not meshes, shapekeys etc).

However IMO perhaps neither can be relied on, if the action is renamed, or created via code and the id_root is not set.

  • $\begingroup$ Thank you! I appreciate the help! $\endgroup$
    – Michael
    Feb 23 at 1:14

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.