The simplest way for this kind of data would be to convert to a .csv (comma-separated-values) file. You can do it easily in Excel with Save As > csv. Then simply access the lines with open(path)
.
This is my input file :

import bpy
for line_number, line in enumerate(open(r'C:\YourFolder\YourFile.csv')):
columns = line.rstrip().split(';') # Replace by a comma ',' if the separator is a comma
if line_number == 0: # Populate the headers
headers = columns
else:
print(f'Line {line_number}:')
for i, column in enumerate(columns):
print(f'{headers[i]} = {column}')
Result :

In your specific case, you can skip the first column and skip lines easily. Keep in mind in python and most programming languages, the first element of a list has an index of 0. There are a few ways to do it but take this for example.
The file :

New code :
import bpy
from mathutils import Vector
vectors = []
for line_number, line in enumerate(open(r'C:\YourFolder\YourFile.csv')):
columns = line.rstrip().split(';') # Replace by a comma ',' if the separator is a comma
if line_number == 0: # Populate the headers
headers = columns
elif line_number % 2 == 0: # Keep only odd lines (which have a pair index since it's zero-based)
vectors.append(Vector((float(c) for c in columns[1:4])))
print(f'Line {line_number + 1}:')
for i, column in enumerate(columns[1::]): # Skip the first column
print(f'{headers[i + 1]} = {column}')
print(vectors)
Result :
