I am new to bpy and I am wondering why the values material_index returns are all zeros.

This is the code I am using:

for obj in bpy.context.selected_objects:
    bpy.context.scene.objects.active = obj
    obj.select = True    
    material_ids = set()
    if obj.data is not None and hasattr(obj.data, "polygons"):
        for polygon in obj.data.polygons:

material_ids is a set that only contains 0

Thank you for your help!

  • 4
    $\begingroup$ polygon.material_index indicates the material to use for this polygon. If your object has only 1 material, all polygons will have the same/first material which index is zero. material_index is considered to be the index in the object material list (not in the overall material list). $\endgroup$ – lemon Oct 14 '19 at 11:22
  • $\begingroup$ and for that matter,also if the mesh object is created for an object with no materials (0 is the default material index value for a face). To be consise it is the index of obj.material_slots Suggest create a test object that has more than one material applied to more than one face. Re code: See no need to select all with operator, or set active object for this. For all meshes in scene = bpy.context.scene ie the set : meshes = set(o.data for o in scene.objects if o.type == 'MESH') Then for each mesh in meshes, material_ids = set(f.material_index for f in mesh.polygons) $\endgroup$ – batFINGER Oct 15 '19 at 12:36

The number 'zero' is just a zero based enumerator (eg: 0th,1st,2nd...etc) for the material used on your polygon.

I think, that the enumerator order corresponds to it's position in the (Materials?) editor scroll box.

If you want to see '1'. Create a new material, select your object or a face of it and "Assign" (Button) the object to the second Material in the list. Re-run your script.

..oh, also "set" only contains unique values. So if all your polgons use material '0' there will only be one entry.

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