2
$\begingroup$

I need extremely accurate representation of real world silver in my curren project.

We can approximate "close enought" in cycles, but this time i need it to be accurate.

Other commercial rendering engines have material presets that sampled from real world materials and provide very close approximation. I played around in Redshift, and it have things like IOR, absorption(k), edge tints, that i assume sampled from real world materials.

Cycles just recently go the principled shader, that includes fresnel effect in itself, before that we used handmade tricks to add fresnel to materials. Plus there is no predefined material presets, like other rendering engines have.

Is it possible to make a physically accurate silver shader at all in cycles? I know i can get close enought by adjusting metalness, roughness, adding slight wear etc. But i'm talking about getting real thing, with real values sampled from real world material.

$\endgroup$
3
  • 1
    $\begingroup$ You will find answer here: blenderartists.org/forum/… $\endgroup$
    – cgslav
    Commented Mar 15, 2018 at 17:20
  • 3
    $\begingroup$ The PBR shader you are looking for is in this answer: blender.stackexchange.com/a/76033/7777. Plug in the real measured n and k values for silver and you are good to go. $\endgroup$ Commented Mar 15, 2018 at 21:14
  • $\begingroup$ A setting like “edge tint” is proof it’s anything but physically modeled. I think here on stackex there is a 5 year old post about thin film interference and it covers metallics as well. Once you want even 10s of aging or oxidization, then you’re anyway back to an artistic impression of it. $\endgroup$
    – Jon
    Commented Oct 4, 2021 at 17:23

1 Answer 1

-1
$\begingroup$

I have one that uses RGB Curves, here are the coords,there are 4 points in the R,G,B and just 2 in color, hope it helps. If not LUXRENDER.

Red = P1(x 0.0, y .96) P2(x .55, y .96) P3(x .83636, y .95) P4(x 1.0, y 1.0)

Green = P1(x 0.0, y .94) P2(x .5, y .94) P3(x .85091, y .94) P4(x 1.0, y 1.0)

Blue = P1(x 0.0, y .91) P2(x .5, y .91) P3(x .81364, y .92) P4(x 1.0, y 1.0)

Color = P1(x 0.0, y 0.0) P2(x 1.0, y 1.0)

$\endgroup$
2
  • 2
    $\begingroup$ Perhaps you could expand this answer to show or tell how these curves are used in a shader tree? $\endgroup$
    – Robin Betts
    Commented Oct 4, 2018 at 15:19
  • $\begingroup$ I want to clarify that LUXRENDER is now called LuxCore. It's great, I higly reccomend it. $\endgroup$ Commented Nov 11, 2018 at 1:45

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .