3
$\begingroup$

Is there any way to convert volumetrics into mesh? I managed to recreate 3D structure from 177 serial images (confocal microscopy) using volumetrics, using guidelines found here

I'm not satisfied with the effect - the structures are blurry and I'm looking for sharp, defined edges.

enter image description here

Any unconventional way to convert this volumetric data into actual mesh?

$\endgroup$
2
$\begingroup$

It is possible to get sharp defined edges using volumetrics - see Give this mesh a uniform thickness on all the tubes and unions. Assuming your source data is to sufficient resolution then it should just be a matter of adjusting the Volume Sampling settings in the Render properties.

Volume Sampling properties

Decrease the Step Size to get better resolution. This is defined in blender units so pick a value that is close to the resolution of your data based on the size of the volume. If the number of steps does not span the volume then increase Max Steps to compensate.

|improve this answer|||||
$\endgroup$
  • 1
    $\begingroup$ Thanks, but the goal is to build a mesh $\endgroup$ – marcheenek Feb 6 '18 at 1:11
  • 1
    $\begingroup$ In that case, I think your best option would be use a python script to use your volumetrics data to place mesh elements such as metaballs at points where the density is above a threshold - and possibly also sized based on the density. The resultant mesh could then be remeshed and/or manipulated to clean it up (depending on how suitable it is to your needs ‘raw’). Without having access to your data and how you’re currently processing it to provide the volumetrics it will be difficult to provide a more detailed solution. $\endgroup$ – Rich Sedman Feb 6 '18 at 7:19
  • $\begingroup$ @marcheenek a similar question was answered here $\endgroup$ – Nathan Aug 14 '18 at 23:29

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.