Skip to main content
Blender

Return to Answer

deleted 7 characters in body
Source Link
J Sargent
J Sargent
  • 19.4k
  • 10
  • 81
  • 131

The result:

Latin

text_string = ''.join([chr(i) for i in range(ord(u'\u0021'), ord(u'\u007E') + 1)])
bpy.ops.font.text_insert(text=text_string)

Cyrilic

text_string = ''.join([chr(i) for i in range(ord(u'\u0410'), ord(u'\u044F') + 1)])
bpy.ops.font.text_insert(text=text_string)

Thanks!

The result:

Latin

text_string = ''.join([chr(i) for i in range(ord(u'\u0021'), ord(u'\u007E') + 1)])
bpy.ops.font.text_insert(text=text_string)

Cyrilic

text_string = ''.join([chr(i) for i in range(ord(u'\u0410'), ord(u'\u044F') + 1)])
bpy.ops.font.text_insert(text=text_string)

Thanks!

The result:

Latin

text_string = ''.join([chr(i) for i in range(ord(u'\u0021'), ord(u'\u007E') + 1)])
bpy.ops.font.text_insert(text=text_string)

Cyrilic

text_string = ''.join([chr(i) for i in range(ord(u'\u0410'), ord(u'\u044F') + 1)])
bpy.ops.font.text_insert(text=text_string)
Added code formatting
Source Link
edit approved Nov 12, 2013 at 8:09
Ocaso Protal
edit approved Nov 12, 2013 at 8:09
Ocaso Protal
  • 359
  • 1
  • 7
  • 21

The result:

Latin

text_string = ''.join([chr(i) for i in range(ord(u'\u0021'), ord(u'\u007E') + 1)]) bpy.ops.font.text_insert(text=text_string)

text_string = ''.join([chr(i) for i in range(ord(u'\u0021'), ord(u'\u007E') + 1)])
bpy.ops.font.text_insert(text=text_string)

Cyrilic

text_string = ''.join([chr(i) for i in range(ord(u'\u0410'), ord(u'\u044F') + 1)]) bpy.ops.font.text_insert(text=text_string)

text_string = ''.join([chr(i) for i in range(ord(u'\u0410'), ord(u'\u044F') + 1)])
bpy.ops.font.text_insert(text=text_string)

Thanks!

The result:

Latin

text_string = ''.join([chr(i) for i in range(ord(u'\u0021'), ord(u'\u007E') + 1)]) bpy.ops.font.text_insert(text=text_string)

Cyrilic

text_string = ''.join([chr(i) for i in range(ord(u'\u0410'), ord(u'\u044F') + 1)]) bpy.ops.font.text_insert(text=text_string)

Thanks!

The result:

Latin

text_string = ''.join([chr(i) for i in range(ord(u'\u0021'), ord(u'\u007E') + 1)])
bpy.ops.font.text_insert(text=text_string)

Cyrilic

text_string = ''.join([chr(i) for i in range(ord(u'\u0410'), ord(u'\u044F') + 1)])
bpy.ops.font.text_insert(text=text_string)

Thanks!

Source Link
mifth
mifth
  • 2.4k
  • 29
  • 37

The result:

Latin

text_string = ''.join([chr(i) for i in range(ord(u'\u0021'), ord(u'\u007E') + 1)]) bpy.ops.font.text_insert(text=text_string)

Cyrilic

text_string = ''.join([chr(i) for i in range(ord(u'\u0410'), ord(u'\u044F') + 1)]) bpy.ops.font.text_insert(text=text_string)

Thanks!